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\renewcommand\datereceived{April 3, 2013}
\renewcommand\dateaccepted{June 23, 2013}

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\markboth{J.\,Kovi\v{c}}{Centrally symmetric convex polyhedra with regular polygonal faces}

\title{Centrally symmetric convex polyhedra with regular polygonal faces}

\author[J.\,Kovi\v{c}]{Jurij Kovi\v{c}\affil{1}\comma\corrauth}

\address{\affilnum{1}\ Institute of Mathematics, Physics and Mechanics, University of Ljubljana, Jadranska 19, SL-1\,000 Ljubljana, Slovenia}

\email{{\tt jurij.kovic@siol.net} (J.\,Kovi\v{c})}


\begin{abstract}
First we prove that the class $C_{I}$ of
centrally symmetric convex polyhedra with regular polygonal faces consists of 4 of the 5 Platonic, 9 of the 13
Archimedean, 13 of the 92 Johnson solids and two infinite families
of $2n$-prisms and $(2n+1)$-antiprisms. Then we show how the presented maps
of their halves (obtained by identification of all pairs of
antipodal points) in the projective plane can be used for
obtaining their flag graphs and symmetry-type graphs. Finally, we
study some linear dependence relations between polyhedra of the
class $C_{I}$.
\end{abstract}

\keywords{map, Platonic solid, Archimedean solid, Johnson
solid, flag graph, convex polyhedron, projective plane}

\ams{37F20, 57M10}



\maketitle



\section{Introduction}

Any centrally symmetric convex (hence: spherical) polyhedron $\mathcal C$ admits identification of pairs of antipodal
points $x$ and $x^{*}$; thus the \emph{map} (i.e. embedding of a
graph in a compact surface) of its \emph{half} $\mathcal C/2 =
\mathcal C/_{x \equiv x^{*}}$ has the Euler characteristic $E = v
- e + f = 1$ (where $v$, $e$ and $f$ are the numbers of the
vertices, edges and faces of the map, respectively) and can be
drawn in a \emph{projective plane} (represented as a disc with
identified antipodal points \cite{PisaServa}). Thus the flag graph
of $\mathcal C/2$ can be easily constructed in the projective
plane, too, while the flag graph of $\mathcal C$ is exactly a
2-sheet cover space \cite{Fulton, Hatcher} over $\mathcal C/2$.

It is well known that the class $C$ of convex polyhedra with
regular polygonal faces consists of 5 \emph{Platonic solids},
13 \emph{Archimedean solids} \cite{PisZit}, the class of 92
non-uniform (i.e. having at least two orbits of vertices)
\emph{Johnson solids} \cite{Johnson} and two infinite families of
prisms and antiprisms. Among these solids we will find a subset
$C_{I} \subset C$ of centrally symmetric solids and present
the maps of their halves $\mathcal C/2$ (obtained by
identification of all pairs of antipodal points) in the projective
plane modelled as a disk with identified antipodal points. From these maps we can deduce the corresponding \emph{flag graphs}
and \emph{symmetry-type graphs} which can be used for the
classification of \emph{maps}, tilings and polyhedra, too
\cite{Lins, Kovic, Massey, Orba}. The maps of the halves of four
Platonic solids (hemi-cube, hemi-octahedron, hemi-dodecahedron,
hemi-icosahedron) and the maps of regular and semi-regular spherical polyhedra
can also be found in Wikipedia (Regular polyhedron, Spherical polyhedron). For convex uniform polyhedra we use the usual notation ($p.q.r.\dots$), describing the cyclical sequence of regular $n$-gonal faces ($n = 3, 4, 5, \dots$) around any vertex.


{\sc Structure:} First some general propositions about centrally symmetric polyhedra
are given (Section 2), and then the
solids $\mathcal C \in C_{I}$ are identified (Section 3). After that the
maps of their halves in the projective plane are presented and we
show how to construct the corresponding flag graph and
symmetry-type graph (Section~4). From these maps the number of faces 3,4,5,6,8,10 for each
$\mathcal C/2$ can be easily found, too. The corresponding vectors
$n = (n_{10},n_{8},n_{6},n_{5},n_{4},n_{3})$ can be used to solve
the following problem (Section 5): Is it possible to take $a$ copies of a
polyhedron $A \in C_{I}$ and $b$ copies of polyhedron $B \in
C_{I}$ and by dissecting their boundary into faces construct a
polyhedron $C \in C_{I}$ so that no faces are left unused?


\section{Centrally symmetric solids}

The sets of vertices, edges and faces of a polyhedron $\mathcal C$
are denoted by $V(\mathcal C)$, $E(\mathcal C)$, $F(\mathcal C)$,
respectively. The \textit{central point} (or the centre) of a polyhedron $\mathcal C \in
C_{I}$  is defined as the point $O$ fixed by the central inversion $c$ preserving $\mathcal C$. The \emph{antipodal elements} (vertices, edges,
faces) of a vertex $v \in V(\mathcal C)$, an edge $e \in
E(\mathcal C)$ and a face $f \in F(\mathcal C)$ are denoted by $c(v)
= v^{*}$, $c(e) = e^{*}$, $c(f) = f^{*}$, respectively. Here are
some necessary (although not sufficient) conditions for $\mathcal
C$ belonging to the class $C_{I}$:


\begin{proposition}\label{nec} Let $\mathcal C \in C_{I}$. Then:
\begin{itemize}
\item[$($i$)$] Any pair of
antipodal edges $e,e^{*}\!\!\in\!E(\mathcal C)$ is parallel;
likewise, any pair of antipodal faces $f,f^{*} \in F(\mathcal C)$
is parallel, too.

\item[$($ii$)$] The numbers $\#v$, $\#e$, $\#f$ of vertices, edges and faces
of $C$ must be even.

\item[$($iii$)$] The numbers of each class of faces with the same number
$(3,4,5,\dots)$ of edges must be even.
\end{itemize}

\end{proposition}

\begin{proof} (i): Let $O$ be the central point of $\mathcal C \in
C_{I}$. For any vertex $v$ let $\vec OV = \vec v$ be the vector
with the starting point $O$ and the ending point in $v$. Let $e(u,v)
\in E(\mathcal C)$. Then $\vec e^{*} = \vec u^{*} - \vec v^{*} =
-\vec u - (- \vec v) = -\overrightarrow{(u - v)} = -\vec e$ for
any $u,v \in V(\mathcal C)$, hence the vectors $\vec e^{*}$ and
$\vec e$ are parallel. Consequently, all the edges of faces $f$ and
$f^{*}$ are parallel, hence $f$ and $f^{*}$ must be parallel, too.

(ii): Obviously $v \neq v^{*}$, $e \neq e^{*}$,$f \neq f^{*}$ for
each $v \in V(\mathcal C)$, $e \in E(\mathcal C)$, $f \in
F(\mathcal C)$.

(iii): Faces $f$ and $f^{*}$ have the same number of edges.
\end{proof}

\begin{corollary} Tetrahedron (3.3.3) and truncated tetrahedron (6.6.3)
are not in the class $C_{I}$.
\end{corollary}

\begin{proof} None of the four faces of (3.3.3) has a parallel face.
The same holds for the four hexagonal faces of (6.6.3). Hence, by
Proposition~\ref{nec}(i), these two solids cannot be in $C_{I}$.
\end{proof}

We shall say that a polyhedron has a rotation $R$ if it is symmetric by rotation $R$. Similarly, it is symmetric by a reflection, we shall say it has a reflection.

\begin{proposition}\label{not} $\,$
\begin{itemize}
\item[$($i$)$] If $\mathcal C \in C$ has
two orthogonal reflection planes $\Pi$ and $\Omega$, but it is not
preserved by the reflection over a plane orthogonal both to $\Pi$
and $\Omega$, then $\mathcal C \notin C_{I}$.

\item[$($ii$)$] If $\mathcal C \in C$ has a rotation $R$ for the angle $\pi$,
but it has not a reflection plane orthogonal to the axis of $R$,
then $\mathcal C \notin C_{I}$.

\item[$($iii$)$] If $\mathcal C \in C$ has a a reflection plane $\Pi$ but it
has not a rotation $R$ for the angle $\pi$ with an axis orthogonal
to $\Pi$, then $\mathcal C \notin C_{I}$.
\end{itemize}
\end{proposition}

\begin{proof} (i): Let the central point $O$ of $\mathcal C$ be the
origin of the Cartesian coordinate system with axes $(x)$ and
$(y)$ in the plane $\Pi$ and $(y)$ and $(z)$ in $\Omega$. Then the
reflections $Z_{\Pi}$ and $Z_{\Omega}$ transform a vertex $v$ with
coordinates $v(x,y,z)$ into $v_{\Pi} = v(-x,y,z)$ and $v_{\Omega}
= v(x,-y,z)$, respectively. If there is also the central inversion
$c$, then $c(v) = v(-x,-y,-z)$. Hence there should also be the
reflection $v(x,y,z) \rightarrow v(x,y,-z)$.

(ii) and (iii) are proved similarly as (i), using the fact that the
rotation $R$ sends the point $(x,y,z)$ into the point $(-x,-y,z)$.
\end{proof}

\begin{proposition}\label{suf} $\,$
\begin{itemize}
\item[$($i$)$] If a polyhedron $\mathcal C \in C$
is symmetrical by the following two operations:
\begin{itemize}
\item[a$)$]  reflection $Z$
over a plane $\Pi$;
\item[b$)$] rotation $R_{\pi}$ for the angle $\pi$
around an axis $a$, orthogonal to $\Pi$;
\end{itemize}
then $\mathcal C \in C_{I}$.
\item[$($ii$)$] If a polyhedron $\mathcal C \in C$ is preserved by the
reflections over three mutually orthogonal planes, then $\mathcal C \in
C_{I}$.
\end{itemize}
\end{proposition}

\begin{proof} (i): The composition of reflection $Z$ and rotation
$R_{\pi}$ sends any point $(x,y,z)$ into its antipodal point
$(-x,-y,-z)$: $ZR_{\pi} = R_{\pi}Z = c$.

(ii): The composition $Z_{1}Z_{2}$ of two reflections $Z_{1}$ and
$Z_{2}$ over two orthogonal planes produces a rotation for the
angle $\pi$ around the axis $a$, which is orthogonal to the third plane,
and we can use (i).
\end{proof}

\begin{corollary}\label{Platon}
The cube (4.4.4), the octahedron (3.3.3.3), the dodecahedron
(5.5.5) and the icosahedron (3.3.3.3.3) are in the class $C_{I}$.
\end{corollary}

\begin{proof}
For (4.4.4) and (3.3.3.3) this is true by Proposition~\ref{suf}(i),
while for (5.5.5) and (3.3.3.3.3) this is true by
Proposition~\ref{suf}(ii).
\end{proof}

All Platonic and Archimedean solids can be obtained from a
tetrahedron using the operations \emph{medial} $Me(\mathcal C)$,
\emph{truncation} $Tr(\mathcal C)$, \emph{dual} $Du(\mathcal C)$
and \emph{snub} $Sn(\mathcal C)$ \cite{PisZit}.

\begin{proposition}\label{MeTrDu} $\,$
\begin{itemize}
\item[$($i$)$] If the solid $\mathcal C$
belongs to the class $C_{I}$, the same holds for its truncation
$Tr(\mathcal C)$, $Me(\mathcal C)$ and dual $Du(\mathcal C)$.

\item[$($ii$)$] However, there are solids such that $\mathcal C \notin C_{I}$
and $Me(C)\in C_{I}$.

\item[$($iii$)$] Likewise, there are solids $\mathcal C \in C_{I}$  such that
$Me(C)\notin C_{I}$ or $Sn(\mathcal C) \notin C_{I}$.
\end{itemize}
\end{proposition}

\begin{proof} (i): From the definitions of operations
$Tr$, $Me$ and $Du$ it follows that they do not have any impact on
the central symmetry of the solid.

(ii): We already know that the tetrahedron (3.3.3) is not in
$C_{I}$, while its medial-the octahedron (3.3.3.3)-is.

(iii): The cube (4.4.4) and the dodecahedron (5.5.5) are in $C_{I}$,
while the snub cube (4.3.3.3.3) and the snub dodecahedron
(5.3.3.3.3) are not, as we can conclude by
Proposition~\ref{not}(ii).
\end{proof}

\begin{proposition}\label{4anti} The 4-antiprism is not centrally symmetric.
\end{proposition}

\begin{proof} Suppose the 4-antiprism is centrally symmetric. Then the central inversion $c$
sends the vertices 1,2,3,4 of one square face into
vertices $c(1) = 1^{*}$, $c(2) = 2^{*}$, $c(3) = 3^{*}$, $c(4) =
4^{*}$ of the other square face (Figure~\ref{why} left).

For any face $f$ the face $c(f) = f^{*}$ has no common point with
the face $f$, hence $v \neq v^{*}$ for any vertex $v$. Since $v$
and $v^{*}$ do not belong to the same face, they cannot be
adjacent vertices. Therefore $A = 3^{*}$ or $A = 4^{*}$. Likewise
$B = 4^{*}$ or $B = 1^{*}$. Likewise $C = 1^{*}$ or $C = 2^{*}$
and $D = 2^{*}$ or $D = 3^{*}$. As soon as we choose one of the
possibilities for $A$, then $B$, $C$ and $D$ are determined by the
above relations.

\begin{figure}[h!]
\centering
\includegraphics[scale=0.7]{4antiprism.eps}
 \caption{\it The 4-antiprism and why it is not centrally symmetric}
 \label{why}
\end{figure}

In the first case (Figure~\ref{why} in the middle), the antipod of
triangle $\Delta(124^{*})$ cannot be
 the triangle $\Delta(1^{*}2^{*}4)$, since the antipod of
 the edge $14^{*}$ is not the edge $1^{*}4$. In the second case (Figure~\ref{why} right),
the antipod of the triangle $\Delta(123^{*})$ is not the triangle
$\Delta(1^{*}2^{*}3)$, since the antipod of the edge $23^{*}$ is
not the edge $2^{*}3$.
\end{proof}

\begin{proposition}\label{ant} The $n$-antiprism belongs to the class $C_{I}$ if and only if $n$ is odd.
\end{proposition}

\begin{proof} If the antiprism $(N.3.3)$, $N \geq 3$ has the central symmetry
$c$, then $c$ sends the vertices of the upper $n$-gon
$1,2,3,4,\dots,n$ into vertices
$1^{*},2^{*},3^{*},4^{*},\dots,N^{*}$ of the upper $N$-gon
(Figure~\ref{antiprismproof}). The antipod of the triangle
$\Delta(1,2,X^{*})$ must be the triangle $\Delta(1^{*},2^{*},X)$.
The vertex $X$ belongs to the upper $N$-gon. Along the upper
$N$-gon we have $X-1$ (grey) triangles $\Delta(1,2,X^{*})$,
$\Delta(2,3,(X+1)^{*})$,\dots, $\Delta(X-1,X,1^{*})$. The same
number of (white) triangles is between vertices $X^{*}$ and $1$
along the lower $N$-gon: $\Delta(X^{*}, (X+1)^{*},2)$,
$\Delta((X+1)^{*},(X+2)^{*},3)$,\dots, $\Delta(1^{*},2^{*},X)$.
Therefore it is $X - 1 \equiv 2 - X$ (mod $N$), hence $2X \equiv
3$ (mod $N$). But this is possible only if $N$ is an odd number,
since the remainder of $2X$ modulo $2n$ is always an even number.
Therefore such labeling of the triangles as shown in
Figure~\ref{antiprismproof} is possible only if $N = 2n+1$, and it
is not possible if $N = 2n$.
\end{proof}

\begin{figure}[h!]
\centering
\includegraphics[scale=0.8]{antiprismproof.eps}
\caption{\it Triangles of a centrally symmetric antiprism}
\label{antiprismproof}
\end{figure}

\section{Determination of the class $C_{I}$}

\begin{theorem} The class $C_{I}$ consists of the following solids:

\begin{itemize}
\item[$($i$)$] four of the five Platonic solids: Cube (4.4.4), Octahedron
(3.3.3.3), Dodecahedron (5.5.5) and Icosahedron (3.3.3.3.3);

\item[$($ii$)$]  nine of the 13 Archimedean solids: Truncated Cube (8.8.3),
Truncated Dodecahedron (10.10.3), Truncated Octahedron (4.6.6),
Truncated Icosahedron (5.6.6), Truncated Cuboctahedron (8.4.6),
Cuboctahedron (4.3.4.3), Icosidodecahedron (5.3.5.3),
Rhombicuboctahedron (4.4.3.4), Rhombicosidodecahe-\linebreak dron (5.4.3.4);

\item[$($iii$)$]  the infinite families of $2n$-prisms and $(2n+1)$-antiprisms;

\item[$($iv$)$]  13 Johnson solids: J15, J28, J31, J36, J39, J43, J55, J59,
J67, J69, J73, J80, J91.
\end{itemize}
All these solids satisfy the condition of Proposition~\ref{suf}(i)
(this will help us to draw the maps of their halves in
Section~\ref{maps}).
\end{theorem}


\begin{proof} (i): These solids are in the class $C_{I}$ by
Corolary~\ref{Platon}.

(ii): All these solids are duals, medials or truncations of solids
being in $C_{I}$, hence by Proposition~\ref{MeTrDu}(i) they are in
$C_{I}$, too.


(iii):  The $2n$-prisms are in $C_{I}$ by Proposition~\ref{suf}(i).
The $(2n+1)$-prisms have odd number of faces 4. The result on
antiprisms is given in Proposition~\ref{ant}.

\begin{figure}[h!]
\centering
\includegraphics[scale=0.7]{J15J91a.eps}
\caption{\it Two centrally symmetric Johnson solids:J15 and J91}
\label{J15J91a}
\end{figure}

(iv): Either using computer programs for polyhedra (like
Great Stella) or with the help of 3D-models of Johnson solids it is
easy to see that all these 13 solids satisfy one or both of the
conditions of Proposition~\ref{suf} (see Table 1). The arguments
why the other 79 Johnson solids are not in the class $C_{I}$ are
given in Table 2.
\end{proof}

\begin{table}[h!]
\centering
\begin{tabular}{|c||c|c||}
  \hline
  % after \\: \hline or \cline{col1-col2} \cline{col3-col4} ...
  Johnson solid $\mathcal C$ & Jxx &   $\mathcal C \in C_{I}$
 \\
   \hline
   \hline

elongated square dipyramid & J15 &  by Proposition~\ref{suf}(ii) \\
\hline
square orthobicupola & J28 &  by Proposition~\ref{suf}(ii)\\
\hline
pentagonal gyrobicupola & J31 & by Proposition~\ref{suf}(i)  \\
\hline
elongated triangular gyrobicupola & J36 & by Proposition~\ref{suf}(i)  \\
\hline
elongated pentagonal gyrobicupola & J39 & by Proposition~\ref{suf}(i)\\
\hline
elongated pentagonal gyrobirotunda & J43 & by Proposition~\ref{suf}(i)\\
\hline
parabiaugmented hexagonal prism & J55 & by Proposition~\ref{suf}(ii)\\
\hline
parabiaugmented dodecahedron & J59 & by Proposition~\ref{suf}(i)\\
\hline
biaugmented truncated cube & J67 & by Proposition~\ref{suf}(ii)\\
\hline
parabiaugmented truncated dodecahedron & J69 & by Proposition~\ref{suf}(i)\\
\hline
parabigyrate rhombicosidodecahedron & J73 &   by Proposition~\ref{suf}(i)\\
\hline
paradiminished rhombicosidodecahedron & J80 & by Proposition~\ref{suf}(i)\\
\hline
bilunabirotunda & J91 &  by Proposition~\ref{suf}(ii)\\
\hline
\end{tabular}
\caption{\it The 13 Johnson solids belonging to the
class $C_{I}$}
\end{table}

And here are the Johnson solids not in the class $C_{I}$:

\begin{table}[h!]
\centering
\begin{tabular}{|c||c|c||}
  \hline
  Johnsons solid $\mathcal C$ & Jxx & eliminated since
 \\
   \hline
   \hline

square pyramid & J1 & only one face $4$\\
\hline
pentagonal pyramid & J2 & only one face $5$\\
\hline
triangular cupola & J3 & only one face $6$    \\
\hline
square cupola & J4 &  only one face $8$\\
\hline
pentagonal cupola & J5 & only one face $10$\\
\hline
pentagonal rotunda & J6 & only one face $10$  \\
\hline
elongated triangular pyramid & J7 & 3 faces with 4 edges   \\
\hline
elongated  square pyramid & J8 & 5 faces with 4 edges   \\
\hline
elongated pentagonal pyramid & J9 & only one face 5\\
\hline
gyroelongated square pyramid & J10 & only one face 4  \\
\hline
gyroelongated  pentagonal pyramid & J11 & only one face 5 \\
\hline
triangular dipyramid & J12 & $v = 5$ odd number \\
\hline
pentagonal dipyramid & J13 & $v = 7$ odd number \\
\hline
elongated triangular dipyramid & J14 & $f = 9$ odd number \\
\hline
elongated pentagonal dipyramid & J16 & 5 faces 4   \\
\hline
gyroelongated square dipyramid & J17 & it contains a 4-antiprism\\
\hline
elongated triangular cupola & J18 & only one face 6\\
\hline
elongated square cupola & J19 & only one face 8\\
\hline
elongated pentagonal cupola & J20 & only one face 10\\
\hline
elongated pentagonal rotunda & J21 & only one face 10   \\
\hline
gyroelongated triangular cupola & J22 & only one face 6   \\
\hline
gyroelongated square cupola & J23 & only one face 8  \\
\hline
\end{tabular}
\end{table}

\begin{table}[h!]
\centering
\begin{tabular}{|c||c|c||}
\hline
gyroelongated pentagonal cupola & J24 & only one face 10  \\
\hline
gyroelongated pentagonal rotunda & J25 & only one face 10   \\
\hline
gyrobifastigium & J26 & by Proposition~\ref{not}(ii)  \\
\hline
triangular orthobicupola & J27 & by Proposition~\ref{not}(ii)\\
\hline
square gyrobicupola & J29 & by Proposition~\ref{not}(iii)\\
\hline
pentagonal orthobicupola & J30 &  by Proposition~\ref{not}(iii)\\
\hline
pentagonal gyrobicupola & J32 & 7 faces with 5 edges\\
\hline
pentagonal gyrocupolarotunda & J33 & 7 faces with 5 edges     \\
\hline
pentagonal orthobirotunda & J34 & by Proposition~\ref{not}(ii)\\
\hline
elongated triangular orthobicupola & J35 & by Proposition~\ref{not}(ii)\\
\hline
elongated square gyrobicupola & J37 & by Proposition~\ref{not}(ii)\\
\hline
elongated pentagonal orthobicupola & J38 & by Proposition~\ref{not}(ii)\\
\hline
elongated pentagonal orthocupolarotunda & J40 & 7 faces with 5 edges\\
\hline
elongated pentagonal gyrocupolarotunda & J41 & 7 faces with 5 edges   \\
\hline
elongated pentagonal orthobirotunda & J42 & by Proposition~\ref{not}(ii)\\
\hline
gyroelongated triangular bicupola & J44 & by Proposition~\ref{not}(ii) \\
\hline
gyroelongated square bicupola & J45 &  by Proposition~\ref{not}(ii)\\
\hline
gyroelongated pentagonal bicupola & J46 & by Proposition~\ref{not}(ii)     \\
\hline
gyroelongated pentagonal cupolarotunda & J47 & 7 faces 5\\
\hline
gyroelongated pentagonal birotunda & J48 & by Proposition~\ref{not}(ii)    \\
\hline
augmented triangular prism & J49 & $v = 7$ odd number  \\
\hline
biaugmented triangular prism & J50 & only one face 4    \\
\hline
triaugmented triangular prism & J51 & $v = 9$ odd number \\
\hline
augmented pentagonal prism & J52 & $v = 11$ odd number   \\
\hline
biaugmented pentagonal prism & J53 & 3 faces 4\\
\hline
augmented hexagonal prism & J54 & $f = 11$ odd number \\
\hline
parabiaugmented hexagonal prism & J56 & by Proposition~\ref{not}(ii)\\
\hline
triaugmented hexagonal prism & J57 & 3 faces 4\\
\hline
augmented dodecahedron & J58 & $v = 21$ odd number \\
\hline
metabiaugmented dodecahedron & J60 & by Proposition~\ref{not}(ii)\\
\hline
triaugmented dodecahedron & J61 & $v = 23$ odd number \\
\hline
metadiminished dodecahedron & J62 & by Proposition~\ref{not}(ii)\\
\hline
tridiminished icosahedron & J63 & $v = 9$ odd number \\
\hline
augmented tridiminished icosahedron & J64 & 3 faces 5\\
\hline
augmented truncated tetrahedron & J65 & 3 faces 6\\
\hline
augmented truncated cube & J66 & 5 faces 8\\
\hline
augmented truncated dodecahedron & J68 & $v = 65$ odd number \\
\hline
metabiaugmented truncated dodecahedron & J70 & by Proposition~\ref{not}(i)\\
\hline
triaugmented truncated dodecahedron & J71 & $v = 75$ odd number \\
\hline
gyrate rhombicosidodecahedron & J72 & by Proposition~\ref{not}(iii)\\
\hline
metabigyrate rhombicosidodecahedron & J74 & by Proposition~\ref{not}(i)\\
\hline
trigyrate rhombicosidodecahedron & J75 & by Proposition~\ref{not}(iii)\\
\hline
diminished rhombicosidodecahedron & J76 & by Proposition~\ref{not}(iii)\\
\hline
\end{tabular}
\end{table}

\begin{table}[h!]
\centering
\begin{tabular}{|c||c|c|c||}
\hline
paragyrate diminished rhombicosidodecahedron & J77 & by Proposition~\ref{not}(iii)\\
\hline
metagyrate diminished rhombicosidodecahedron & J78 & by Proposition~\ref{not}(iii)\\
\hline
bigyrate diminished rhombicosidodecahedron  & J79 & by Proposition~\ref{not}(iii)\\
\hline
metadiminished rhombicosidodekahedron & J81 & by Proposition~\ref{not}(i)\\
\hline
gyrate bidiminished rhombicosidodekahedron & J82 & by Proposition~\ref{not}(iii)\\
\hline
tridiminished rhombicosidodekahedron & J83 & $v = 45$ odd number \\
\hline
snub disphenoid & J84 & by Proposition~\ref{not}(i)\\
\hline
snub square antiprism & J85 & by Proposition~\ref{not}(ii)\\
\hline
sphenocorona & J86 & by Proposition~\ref{not}(i)\\
\hline
augmented sphenocorona & J87 & by Proposition~\ref{not}(iii)\\
\hline
augmented sphenocorona & J88 & by Proposition~\ref{not}(i)\\
\hline
hebesphenomegacorona & J89 & 3 faces 4 \\
\hline
disphenocingulum & J90 & by Proposition~\ref{not}(i)\\
\hline
triangular hebesphenorotunda & J92 & only one face 6\\
\hline
\end{tabular}
\caption{\it The 79 Johnson solids not being in the
class $C_{I}$}
\end{table}


\section{Maps of $\mathcal C/2$, $\mathcal C \in C_{I}$
in the projective plane}\label{maps}

\begin{figure}[h!]
\centering
\includegraphics[scale=0.55]{Platproj2.eps}
\caption{\it The halves of Platonic solids in the projective plane}
\label{Platproj}
\end{figure}

\begin{figure}[h!]
\centering
\includegraphics[scale=0.55]{Aproj3.eps}
\caption{\it The halves of Archimedean solids in the projective plane}
\label{PAproj}
\end{figure}

\begin{figure}[h!]
\centering
\includegraphics[scale=0.55]{ten1.eps}
\label{maps10a}
\end{figure}

\begin{figure}[h!]
\centering
\includegraphics[scale=0.55]{ten2b.eps}
\caption{\it The halves of Johnson solids in the projective plane}
\label{maps10}
\end{figure}

The flag graphs of halves of solids $\mathcal C \in C_{I}$ can now
be deduced from Figures~\ref{Platproj}, ~\ref{PAproj} and
~\ref{maps10}. For J31 this is done in Figure ~\ref{flaggraphJ15}.
Now it is easy to obtain the symmetry-type graphs of any $\mathcal
C \in C_{I}$. For J15 this is done in Figure~\ref{symmetrygraphJ15}.


\begin{figure}[h!]
\centering
\includegraphics[scale=0.55]{prizmainantiprizma2.eps}
\caption{\it The halves of 6-prism and 5-antiprism in the projective plane}
\label{pa}
\end{figure}


\begin{figure}[h!]
\centering
\includegraphics[scale=0.5]{flaggraphJ15.eps}
\caption{\it Flags and flag graph of (J15)/2}
\label{flaggraphJ15}
\end{figure}

\begin{figure}[t]
\centering
\includegraphics[scale=0.55]{symgraph.eps}
\caption{\it Representative flags of orbits and symmetry-type graph of J15}
\label{symmetrygraphJ15}
\end{figure}


\section{Spectral analysis of faces of $\mathcal C/2$ for $\mathcal C \in C_{I}$}\label{spectra}

\begin{definition} For any polyhedron $\mathcal P$ with regular faces having at most $n$ vertices let
the vector $\textbf{s}(\mathcal C) = (f_{n},\dots,
f_{6},f_{5},f_{4},f_{3})$ denote its »spectral vector, counting
the numbers $f_{i}$ of its faces with $i$ vertices. In the
corresponding »spectral codes« $S(\mathcal P)$ (see the right
column of Table 3) only the nonzero numbers $f_{i}$ are given.
\end{definition}
\vspace*{-.3cm}
\begin{table}[h!]
\centering
\begin{tabular}{|c|c|c|c|c|c|c|c|}
  \hline
  % after \\: \hline or \cline{col1-col2} \cline{col3-col4} ...
  $\mathcal C$ & $n_{10}$ & $n_{8}$ & $n_{6}$ &$n_{5}$ & $n_{4}$ & $n_{3}$ &
  $S(\mathcal C/2)$\\
  \hline
   \hline
$(4.4.4)$ &  &  &  & & 3 &  & $4_{3}$\\
  \hline
$(5.5.5)$ &  &  &  &6 &  &  &$5_{6}$\\
  \hline
$(3.3.3.3)$ &  &  &  & &  & 4 &$3_{4}$\\
  \hline
$(3.3.3.3.3)$ &  &  &  & &  & 10 &$3_{10}$\\
  \hline
  \hline
$(4.6.6)$ &  &  & 4 & & 3 &  &$6_{4}4_{3}$\\
  \hline
$(5.6.6)$ &  &  & 10 & 6 &  &  &$6_{10}5_{6}$\\
  \hline
$(8.8.3)$ &  & 3 &  &  &  & 4 &$8_{3}3_{4}$\\
  \hline
$(10.10.3)$ & 6 &  &  &  &  & 10 &$10_{6}3_{10}$\\
  \hline
$(8.4.6)$ &  & 3 & 4 &  & 6 &  &$8_{3}6_{4}4_{6}$\\
  \hline
$(3.4.4.4)$ &  &  &  &  & 9 & 4 &$4_{9}3_{4}$\\
  \hline
$(4.3.4.3)$ &  &  &  &  & 3 & 4 &$4_{3}3_{4}$\\
  \hline
$(5.3.5.3)$ &  &  &  & 6 &  & 10 &$5_{6}3_{10}$\\
  \hline
$(5.4.3.4)$ &  &  &  & 6 & 15 & 10 &$5_{6}4_{15}3_{10}$\\
  \hline
  \hline
J15 &  &  &  &  & 2 & 4 &$4_{2}3_{4}$\\
  \hline
J28 &  &  &  &  & 5 & 4 &$4_{5}3_{4}$\\
  \hline
J31 &  &  &  & 1 & 5 & 5 &$5_{1}4_{5}3_{5}$\\
  \hline
J36 &  &  &  &  & 6 & 4 &$4_{6}3_{4}$\\
  \hline
J39 &  &  &  & 1 & 10 & 5 &$5_{1}4_{10}3_{5}$\\
  \hline
J43 &  &  &  & 6 & 5 & 10 &$5_{6}4_{5}3_{10}$\\
  \hline
J55 &  &  &  &  & 4 & 4 &$4_{4}3_{4}$\\
  \hline
J59 &  &  &  & 5 &  & 5 &$5_{5}3_{5}$\\
  \hline
J67 &  & 2 &  &  & 5 & 8 &$8_{2}4_{5}3_{8}$\\
  \hline
J69 & 5 &  &  &  & 5 & 15 &$10_{5}4_{5}3_{15}$\\
\hline
J73&  &  &  & 6 & 15 & 10 &$5_{6}4_{15}3_{10}$\\
  \hline
J80 & 1 &  &  & 5 & 10 & 5 &$10_{1}5_{5}4_{10}3_{5}$\\
  \hline
J91 &  &  &  & 2 & 1 & 4 &$5_{2}4_{1}3_{4}$\\
  \hline
\end{tabular}
\caption{\it Spectral vectors of
$\mathcal C/2$ for $\mathcal C \in C_{I}$}
\end{table}


\subsection{Linear dependence relations between polyhedra} \label{linear}

The concept of the spectral vector paves the way to the study of
linear dependence relations between any polyhedra.

\begin{definition}\label{linear}
Polyhedra $P_{1},  \dots, P_{m}$ are linearly
dependent, if their corresponding spectral vectors
$\textbf{s}(P_{i})$ are linearly dependent.
\end{definition}

In other words: there are
$a_{1},\dots,a_{m} \in \mathbb Z$ not all equal to zero such that
\[
a_{1}\textbf{s}(P_{1}) +  \dots +
a_{m}\textbf{s}(P_{m}) = \textbf{0}.
\]
Using spectral vectors we can also define such concepts as
``collinearity'' and ``coplanarity'' of polyhedra.

\begin{definition}\label{coplanar}
Let $A, B, C$ be any polyhedra. If it is possible to take $a$
copies of $A$ and $b$ copies of $B$ and by dissecting their
boundary into faces construct $c$ copies of a polyhedron $C$ so
that no faces are left unused, we say that the solids $A$, $B$,
$C$ are \emph{coplanar} and we write this symbolically as $aA + bB
= cC$. Similarly, we write $aA = bB$ and say that $A$ and $B$ are
collinear, if the relation $a\textbf{s}(A) = b\textbf{s}(B)$ holds
for their corresponding spectral vectors.
\end{definition}

Using the information gathered in Table 3 we can now easily solve
questions about linear dependence relations polyhedra from $C_{I}$
(since for the corresponding spectral vectors we obviously have
the relation $\textbf{s}(\mathcal C) = 2 \textbf{s}(\mathcal
C/2)$.

\begin{example} Are the polyhedra J55, J59 and J73 coplanar? To answer
this we have to solve the vector equation $a \textbf{s}($J$55/2) +
b \textbf{s}($J$59/2) = c \textbf{s}($J$73/2)$, or, equivalently,
$a(4_{4} + 3_{4}) + b(5_{5} + 3_{5}) = c(5_{6} + 4_{10} +
3_{10})$. From this we obtain the following system of three linear
equations: $5b = 6c$, $4a = 10c$, $4a + 5b = 10c$. Thus $b =
6c/5$, $a = 5c/2$ and $4(5c/2) + 5(6c/5) = 10c$, hence $10c + 6c =
10c$ and $c = 0$. Thus J55, J59 and J73 are not coplanar.

Some examples of coplanar solids from $C_{I}$ are:
\begin{itemize}

\item[] J31, J59 and J59, since $5_{1}4_{5}3_{5} + 5_{5}3_{5} =
5_64_{5}3_{10}$, hence J31 + J59 = J43;

\item[] J31, (4.4.4) and J39, since $3\cdot 5_{1}4_{5}3_{5} + 5\cdot 4_{3}
= 3\cdot 5_{1}4_{10}3_{5}$, hence  $3\cdot $J$31 + \linebreak 5\cdot(4.4.4) =
3\cdot $J$39$;

\item[] J15, (3.4.4.4) and J39, since $4\cdot 4_{2}3_{4} + 3\cdot
4_{9}3_{4} = 7\cdot 4_{5}3_{4}$, hence  $4\cdot $J$15 + \linebreak
3\cdot(3.4.4.4) = 7\cdot $J$28$.
\end{itemize}
Other ``linear polyhedral equations'', as $aA + bB = cC + dD$, may
be treated in a similar way, too.
\end{example}


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\end{document}

